BIOL 1406

PreLab 9a.2

How are vectors used in gene cloning?

Gene cloning is a method for making many identical copies of a gene by inserting the gene into a living host cell. Under appropriate conditions, the host cell will replicate the “foreign” DNA along with its own DNA whenever it divides. With each cell division, the number of copies of the “foreign” gene doubles. This technique permits biologists to produce large quantities of a single gene so that they can study the gene in detail. Biologists can also induce cells containing cloned genes to produce large quantities of the protein coded for by the gene. By making large amounts of “proteins to order” in this way, scientists can study the protein’s structure and function. They can also produce large quantities of a protein for commercial or medical use. For example, scientists can produce proteins that are used as enzymes in commercial food processing techniques or proteins that can be used to treat disease.

Diagram of plasmid pSKU146 shows potential protein coding regions (arrows) and recognition sites for selected restriction enzymes

 

Vectors are tools used by molecular biologists to insert genes or pieces of foreign DNA into host cells. Two naturally occurring vectors that are used to insert foreign DNA into bacterial cells are bacteriophages and plasmids. Bacteriophages (or phages, for short) are viruses that infect bacterial cells by injecting their genetic material into the bacterial cell. Plasmids are small circles of DNA that are sometimes present in bacteria in addition to the larger circle of DNA that constitutes the main bacterial genome. Many bacteria readily absorb plasmids from the environment under appropriate conditions. In order to use a phage or plasmid as a vector, scientists combine the DNA they wish to clone with the DNA of the vector. When DNA from 2 different sources is combined, the resulting DNA is called recombinant DNA. If recombinant DNA gets inside a host cell, it can replicate along with the DNA of the host cell.

In this lab you will be working with a plasmid called pUC18. This plasmid includes 2 genes. One gene confers resistance to the antibiotic ampicillin. Bacteria that contain this gene are able to grow in the presence of ampicillin, while bacteria that lack this gene are not. The second gene is called the lacZ gene. The lacZ gene codes for  β–galactosidase, an enzyme normally used by E. coli to digest lactose. However, when bacteria with this gene are grown in a medium containing a synthetic analog of lactose called Xgal, the enzyme digests Xgal and releases a blue compound. Therefore, bacteria with a functional lacZ gene will produce a blue color when grown in the presence of Xgal.

Diagram of a bacteriophage

 


The following procedure describes how scientists can use pUC18 as a vector to insert phage DNA into E. coli cells:

  1. A restriction enzyme called EcoRI is used to cut the pUC18 plasmids. EcoRI cuts each circular plasmid at a single location, somewhere within the lacZ gene. Because EcoRI cuts each plasmid at a single location, a linear piece of DNA is formed. EcoRI is also used to cut the phage DNA at a single location:
  2.  

  3. The linearized plasmids and the phage DNA are mixed together. Complementary sticky ends allow the pieces of DNA to anneal in five possible combinations.
  4. Note that only combination “C” contains recombinant DNA. Recombinant DNA is made by joining DNA from 2 different sources, in this case, the plasmid and the phage. All the other combinations (A, B, D, and E) contain non-recombinant DNA (DNA from one source only.)

     

  5. An enzyme called DNA ligase is used to join the annealed pieces together.
     
  6. After the pieces of DNA are joined back together, they are incubated with E. coli cells. During incubation, some E. coli cells will absorb no DNA, some will absorb non-recombinant DNA (either plasmid DNA alone or phage DNA alone), and some will absorb a recombinant plasmid. To screen for bacterial cells that contain a recombinant plasmid, the bacteria are placed on growth medium that contains ampicillin and Xgal. There are 3 possible outcomes:
  7. a) E. coli cells that absorbed no DNA at all, as well as those that absorbed only phage DNA (combinations B and E above) will lack the gene for ampicillin resistance (present only on the plasmid.) Therefore, these bacteria will not grow and no bacterial colonies will be formed.

    b) E. coli cells that absorbed only plasmid DNA (combinations A and D above) will have the gene for ampicillin resistance and the lacZ gene. The gene for ampicillin resistance allows them to grow and form colonies. The lacZ gene produces β–galactosidase which digests Xgal and releases compound “X”, which is blue. Therefore, these E. coli cells will produce blue colonies.

    c) E. coli cells that absorbed a recombinant plasmid (combinations C above) will have the gene for ampicillin resistance (present on the plasmid.) Therefore they will grow and produce colonies. However, the lacZ gene on the plasmid has been cut into 2 pieces by the restriction enzyme and a piece of phage DNA has been inserted between the 2 parts of the lacZ gene. This inactivates the lacZ gene, meaning no β–galactosidase will be produced. Therefore, Xgal is not digested, no blue color is produced, and the colonies remain white.

 

Use the interactive exercise below to learn how foreign DNA can be inserted into a plasmid.

 

Your Turn
What is gene cloning?

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Under ideal conditions the bacterium E. coli can undergo binary fission every 20 minutes. If one E. coli cell containing a foreign gene is inoculated into a flask of nutrient broth and allowed to replicate for 12 hours, how many copies of the foreign gene would it produce?

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Why are scientists interested in cloning genes?

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Name and describe 2 vectors that are commonly used to insert foreign DNA into bacterial cells.

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What is recombinant DNA?

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Briefly explain how scientists can produce recombinant DNA.

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